Physics 2D motion parts ABC. thank you ate: 924/2018 11:59:00 PM End Date: 10/1/

Question

Physics 2D motion parts ABC. thank you

ate: 924/2018 11:59:00 PM End Date: 10/1/2018 11:59:001 Third Assignment 2D Begin Date: 9/10/2018 12:01:00 AM-- Due D (4%) Problem 23: An arrow is shot from a height of 1.35 m toward a cliff of height H It is shot with a velocity of32 m/s at an angle of 60f above the horizontal It lands on the top edge of the cliff 3.63 s later D, à 33% Part (a) What is the height Hof the cliff in m? sinO cos0 an cotan asinOacos0 atan0 aca sinh0 cosho tanhOcotanh0 Degrees Radians Submit Hant I give up Elin ts;_ deduction per hit. Hints retaining: Feedback: dedcticn per feedback 33% Part (b) What is the maximum height reached by the arrow along its trajectory in meters? á 33% Part (c) what is the arrow's speed just before hitting the cliff in ms?

Explanation / Answer

y = H-1.85 ; x =? ; U = 32 m/s; @ = 60 deg; t = 3.63 s

Ux = 32cos60 = 16m/s ; Uy = 32sin60 = 27.7 m/s

a)

using s = ut + 1/2 at^2 for vertical motion

H-1.85 = 27.7 x 3.63 - 1/2 x 9.8 x 3.63^2

H = 37.83 m

b)

h = Uy^2/2g = 27.7^2/2x9.8 = 39.15m

hmax = 1.85 + 39.15 = 41m

c)

Vy = Uy + at

= 27.7 -9.8 x 3.63 = -7.874 m/s

V^2 = Vx^2 + Vy^2 = 16^2 + 7.874^2

V = 17.83 m/s

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---