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Please answer part B if you can 4. A particle of mass m is constrained to move o

ID: 1884564 • Letter: P

Question


Please answer part B if you can 4. A particle of mass m is constrained to move on a circle of radius R. The circle in tur rotates with constaut angular velocity about an axis orthogonal to its plane and passing through some point P on its circumference. Show that (a) The motion of the particle with respect to an axis passing through P and the center of the circle is that of a planar pendulum in uniform gravitational field. (b) Calculate the total energy E and angular momentum L. Show that E -L-s is a constant of the motion. Are E&L themselves constants?

Explanation / Answer

4. givne particle of mass m

mopves in a circle of radius R

circle mocves at angular speed omega about a point P on its circumference

a. let the angle of the particle with the center of the circle be phi

angle of the circle with respect to the axis P and refrence axis be theta

theta' = omega

phi' = w

then

x = Rcos(theta) + Rcos(theta + phi)

y = Rsin(theta) + Rsin(theta + phi)

x' = -Rsin(theta)*omega - R*sin(theta + phi)(omega + w)

y' = Rcos(theta)*omega + Rcos(theta + phi)(omeg a+ w)

as we can see

x = R(cos(theta) + cos(theta + phi)) = 2R*cos(theta + phi/2)cos(phi/2)

y = 2R*sin(theta + phi/2)cos(phi/2)

r = sqrt(x^2 + y^2) = 2R*cos(phi/2)

hence r the position vecotr about the asxis P follows SHM equation

b. total energy = E

E = < 0.5kr^2 >

now

phi = wt

hence

E = <0.5k*4R^2*cos^2(wt/2)>

here

sqrt(k/m) = w/2

k = mw^2/4

<E> = 0.5mw^2*R^2

as average energy <E> is independent of time, the E is constant

also

L = m r x v = 2Rcos(phi/2) [cos(theta + phi)i + sin(theta + phi)j] x [x'i + y'j]

L = m r x v = 2Rmcos(phi/2) [cos(theta + phi)(Rcos(theta)*omega + Rcos(theta + phi)(omeg a+ w)) - sin(theta + phi) -Rsin(theta)*omega - R*sin(theta + phi)(omega + w)]k

L.omega = 2Rmcos(phi/2) [cos(theta + phi)(Rcos(theta)*omega + Rcos(theta + phi)(omeg a+ w)) - sin(theta + phi) -Rsin(theta)*omega - R*sin(theta + phi)(omega + w)]*omega ( both are parallel)

L.omega = 2Rmcos(phi/2) [cos(theta + phi)(Rcos(theta)*omega + Rcos(theta + phi)(omeg a+ w)) - sin(theta + phi) -Rsin(theta)*omega - R*sin(theta + phi)(omega + w)]*omega can be shown to be constant of motion by showing

d(L.omega)dt = 0

henceE - L.omega is is constnat of motion and E and L are individually conserved as well