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Consider the x-y plane to be a mirror with a medium exhibiting a constant refrac

ID: 1884707 • Letter: C

Question

Consider the x-y plane to be a mirror with a medium exhibiting a constant refractive index above it. Set up the calculation using point A and B as the start and end points a height H above the x-y plane. Consider points A' and B' directly beneath points A and B, but lying in the x-y plane. You must consider light reflecting at point P somewhere in the x-y plane. Suppose the x coordinate of P is fixed: x=X, prove that the minimum path length (AD+ PB) for this arbitrary Xp is given by yp -0. Hint: To simplify things, no loss of generality is incurred by making points A and B directly above the x axis with point A at x=0 and point B at x-2 L from point A i.e. set Point A as (0,0,H) and Point B as (21,0, H). In this situation P is at (Xp, yp,0) where Xpis fixed. See the hint diagram (2L,0,H) 2L (0,0,H

Explanation / Answer

Let the co-ordinates of P be xp and yp lying in x,y plane

x-y plane is a mirror.

we can consider the line joing A,B of height H directly above the x-axis i.e projection of this line on to x-y plane is on the x-axis. i.e the line joining A' and B' , further we choose the point A* as our origin.

This makes no difference to the solution as we have only selectd a simplified co-odinate system.

given that xp is fixed

co-ordinates of A (0,0,H) that of B (2L,0,H)

we take 2L as the distance between A and B

now light from A refelcted at P reaches B

angle of incidence = angle of reflection

APB is an isoceless traingle and AP =BP

path of the light = 2AP

A = (0,0,H) and P = (xp,yp,0)

AP2 = xp2 + yp2 + H2  

in this expression for AP , xp is fixed , x co-ordinate of P

H - height of the line AB is fixed

the only variant is yp, y co-rdinated of P

AP2 is +ve and all quantites on RHS or +ve

hence AP2 is minimum for yp =0

=> for minimum path of light yp =0