ID Practice Problems 3 Probabili -Search in Document Insert Design Layout Refere
ID: 188683 • Letter: I
Question
ID Practice Problems 3 Probabili -Search in Document Insert Design Layout References Mailings Review View Home Arial Styles Styles Pane Paste 3. In nature, individual plants of Riectritis congesta bear either winged or wingless fruits. Three individual plants were collected from nature (thus not necessarily pure breeding) before flowering and were either crossed or self-pollinated. The results are shown below Number of Cross Parental Winged #1 (selfed) Winged #2 (selfed) Wingless #1 (selfed) Winged #1 X Wingless #1 winged #2 x wingless #1 Wi 91 90 80 161 31 24 a) Give a concise genetic hypothesis for the inheritance of fruit shape as determined from these crosses (include the number of genes, number of alleles, and dominance relationship between alleles).2 b) Give the most probable genotypes of: (define your alleles)2 Winged #1 Winged #2 Wingless #1 c)If you self-pollinate the winged #2 plant and planted six seed, what is the probability of obtaining in these six seeds? 1) 2) 3) all winged progeny one wingless and 5 winged progeny at least one wingless progeny Page 2 of 3 354 Words English (US)Explanation / Answer
a. From the given data, it is apparent that the particular trait is controlled by one pair of alleles, with a single gene responsible for the trait. There is one dominant allele and one recessive. Winged #1 appears to have a homozygous dominant orientation, as none of the offspring of the self-cross show the other trait.
b. Assuming W as the dominant allele and w as the recessive allele:
Winged #1: WW
Winged #2: Ww
Wingless #1: ww
c. 1. For getting one winged offspring, the probability is 3/4
For getting 6 winged offspring, the probability is (3/4)6
2. One wingless and 5 winged: 1/4 x (3/4)5
3. Atleast one wingless progeny: 1 - (3/4)6