I toss a ball vertically in the air at t=0s. It goes up for 2s and then falls ba

Question

I toss a ball vertically in the air at t=0s. It goes up for 2s and then falls back down to my hand. Answer the following questions (Questions 5-11) about the ball's motion. Set the upwards direction as positive and be careful to get the signs right for accelerations, velocities and positions. The following equations will prove useful: v = v0 + at x = x0 +v0t + 1/2 at2 g = 9.8 m/s2 In this problem, x will describe positions in the vertical direction. At t = 2s, what is the velocity of the ball? At t= 2s, what is the acceleration of the ball? (Important: is the sign positive or negative?) What was the initial velocity of the ball when it left my hand? What is the maximum height that the ball reaches above my hand? (set x0, the height of my hand, to be at 0m) How long does it take for the ball to return to my hand from the peak?

Explanation / Answer

-9.8 m/s^2 as g is always downward u=9.81*2=19.62 m/s s=19.62^2/(2*9.81)=19.62 2 sec

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