I\'m trying to find the C.G. for this man given this information. Figure 4.66. T
ID: 1901544 • Letter: I
Question
I'm trying to find the C.G. for this man given this information.
Figure 4.66. The man shown in Fig.4.65 is now bending over so that his back is nearly horizontal. Note that his center of gravity is still over his feet. (Adapted from Williams and Listener.) that the friction is negligible and that the pulleys and lopes are massless. What applied force Fa is necessary to lift the weight w in Fig. 4.67? The forces on pulley I are shown in Fig. 4.67b. The rope is continuous, and the tension on both sides of the pulleys is the same. If the constant speed, the system 2Fa - w = 0, and Fa = w/2 half the weight, and the What applied force Fa weight w with the pulley the mechanical advantage Again the tension in ea the same, so 4Fa - w = 0 cal advantage for this syExplanation / Answer
xcm = 0.593 * 0.10 + 0.053*0.14+0.043 *0.24 +0.193 *0.12 +0.118 *0.10
xcm = 0.112 h
ycm = 0.593 *0.70 +0.053 *0.75 +0.043 *0.64 +0.193*0.42 +0.118 *0.19
ycm = 0.586 h