Block m is released and allowed to accelerate down the slant surface of wedge 2m
ID: 1902425 • Letter: B
Question
Block m is released and allowed to accelerate down the slant surface of wedge 2m.As it does so the wedge accelerates (of Course) to the right. Chord C is a continuous cord, parallel to the slant surface in one part and horizontal in the other part. Assume forces concurrent on each body (i.e, one normal force under mass 2m, and one normal force between mass m and mass 2m). Find the acceleration of the wedge, in terms of ? and g (and m?) Hint:Note that m has two accelerations not at right angles; therefore, one of the accelerations will have to be resolved into components. Check that you have found 5 forces on the wedge.
Explanation / Answer
a1=acc of wedge, a=acc of block along the inclined
ma=mgsin + ma1cos{ma1=pseudo force on block when viewed from wedge reference frame} - T
ma1sin+N=mgcos
T(1-cos)+Nsin=2ma1
T=3ma1
Solve to get a1 and a.
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