A 6.30g bullet traveling at 490m/s embeds itself in a 1.81kg wooden block at res

Question

A 6.30g bullet traveling at 490m/s embeds itself in a 1.81kg wooden block at rest on a frictionless surface. The block is attached to a spring with k - 76.0N/m (see the figure). (Figure1) Find the period. Express your answer with the appropriate units. Find the amplitude of the subsequent simple harmonic motion. Express your answer with the appropriate units. Find the total energy of the bullet + block + spring system before the bullet enters the block. Express your answer with the appropriate units. Find the total energy of the bullet + block + spring system after the bullet enters the block. Express your answer with the appropriate units.

Explanation / Answer

a)T=2sqrt(m/k)=0.97s

b)Conserving momentum,

mv=(M+m)V

V=1.70m/s

Conserving energy,

0.5(M+m)V2=0.5kx2

x=0.263m=26.3cm

c)Total energy before collision=0.5mv2=756.3J

d)Total energy after collison=0.5kx2=2.63J

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