Media Links CommentsHeader &Footer; Use the following information to answer the
ID: 190339 • Letter: M
Question
Media Links CommentsHeader &Footer; Use the following information to answer the questions below: Below are two graphs indicating light attenuation in water (at left), and in a forest (at right) Both indicate the amount of light available relative to the amount of light shining on the surface of the water (Light (% surface) or forest canopy (Available Light (Ali). For the following questions you are two compare light attenuation in water as one dives downward to light attenuati Note that the top of the forest canopy is 26 meters above the ground, thus the data point at 24 m is two meters below the top of the canopy. on in a forest as one rappels from the top of a canopy down toward the forest floor. 1) At 10 meters from the water surface / top of canopy, approximately what % of surface light would you expect to be available in both the water and the forest? 2) At which water depth / distance from the top of canopy (not distance above the ground) would you expect light to be at 50% of water/canopy surface quantity 3) Ground level in the forest would have same light quantity as which depth in the water? Light (% surface) d States)Explanation / Answer
Hi,
To solve this question, use the given graphs. water = graph 'a'. forest canopy = graph 'b'.
1). 10m from water surface, the light available=
see the 10 on Y axis on graph on the left. Note the corresponding value in the graph on X axis. It is = 70% of the light at surface.
similarly, on right graph, 10m from canopy = 26 - 10 = 16 m the available light = around 0.15 or 15%.
2) Light is = 50% of surface / canopy.
In water - 50% on X axis corresponds to 20m.
In forrest - 50% (0.5) on X axis corresponds to 23m.
3)Ground level of forest , the ligth intensity = 0.1 = 10%
In water, the 10% of ligth is present at depth of 60m from the surface.