A small block of mass mA = M is released from rest at the top of the curved fric
ID: 1910003 • Letter: A
Question
A small block of mass mA = M is released from rest at the top of the curved frictionless ramp shown above. The block slides down the ramp and is moving with a speed 2.9v0 when it collides with a larger block of mass mB = 0.5M at rest at the bottom of the incline. The larger block moves to the right at a speed 1.9v0 immediately after the collision. Express your answers to the following questions in terms of the given quantities and fundamental constants. (Use v_0 for v0 and g for acceleration due to gravity)
(a) Determine the heighthof the ramp from which the small block was released.
(b) Determine the velocity of the small block after the collision.
(c) The larger block slides a distanceDbefore coming to rest. Determine the value of the coefficient of kinetic friction ? between the larger block and the surface on which it slides.
(d) Indicate whether the collision between the two blocks is elastic or inelastic. Justify your answer in your notebook.
Explanation / Answer
A small block of mass M is released from rest at the top of the curved frictionless ramp shown above. The block slides down the ramp and is moving with a speed 3.5 v0 when it collides with a larger block of mass 1.5M at rest at the bottom of the incline. The larger block moves to the right at a speed 2 v0 immediately after the collision. a. what is the height h of the ramp from which the block was released b. what is the speed of the small block after collision c. the larger block slides a distance D before coming to rest. determind value of the coefficient of kinetic friction between the larger block and surface on which it slides a) 3.5 vo = v [2gh] h = 12.25 v0^2 / 2g = 0.625 v0^2. b) Initial momentum of the two 3.5 M v0 + 0. Final momentum 1.5 M 2v0+M w 1.5 M 2v0 +M w = 3.5 M v0 3 v0 +w = 3.5 v0 w = 0.5 v0 c} w^2 = 2aD. a = 0.125 v0^2/ D µ = a/g = 0.125 v0^2 / D g