Single Mirror System A spherical mirror forms an image of an arrow at x = X2 = -
ID: 1914567 • Letter: S
Question
Single Mirror System A spherical mirror forms an image of an arrow at x = X2 = -74.1 cm. The mirror is represented in the drawing as a plane at x = 0. The tip of the object arrow is located at What is f, the focal length of the mirror? If the mirror is concave f is positive. If the mirror is convex, f is negative. What is Y2, the y co-ordinate of the image of the tip of the arrow? The object arrow is now moved such that image distance doubles, i.e., Ximage, new = -148.2 cm. What is yimage, new, the new y co-ordinate of the image of the tip of the arrow? The object arrow is now moved to x = x1, new = -18.9 cm. What is y2,new, the new y co-ordinate of the image of the arrow? Which of the rays in the diagram is not reflected as shown?Explanation / Answer
v = -74.1 cm u = -97 cm so, 1/v + 1/u = 1/f f = -42.0087 cm M = -v/u = -0.7639 so, hi = -4.0029 cm Now, v is doubled... so, v = -148.2 cm f = -42 cm u = -58.61 cm So, M = -2.528 hi = -13.24 u = -18.9 cm f = -42 cm v = 34.36 cm M = -v/u = 1.8181 hi = M*ho = 9.527 cm Final Answers: 1) -42.0087 cm 2) -4.0029 cm 3) -13.24 cm 4) 9.527 cm 5) (b)...it is wrong...