In pheasants, there are three plumage variants: light, buff and ring. The table

Question

In pheasants, there are three plumage variants: light, buff and ring. The table below gives the results of several crosses between parents of unknown genotype. Use this information to answer Questions 8-9 Parents Offspring male x female 1. light x light 2. light x buff 3. buff x light 4. light x ring 5. buff x buff Males all light ½ light, ½ buff ½ light, ½ buff all buff ½ buff, 1/4 light, 1/4 ring all ring Females all light ½ light, ½ buff ½ light, ½ buff all buff ½ buff, 1/4 light, 1/4 ring all ring 6. ring X ring 8. If you were to cross the male parent from family #6 with the female parent from family #3, what offspring ratio would you expect? a) all buff b) ½ light, ½ ring c)% light, ½ buff d)% buff, ½ ring e) ½ buff, 1/4 light, 1/4 ring 9. What is the phenomenon depicted in families 1-6 called? a) mutation b) epistasis c) variable penetrance d) variable expressivity e) incomplete dominance

Explanation / Answer

Question 8:

When male with ring is crossed with half white half buff female, the expected phenotype will be

e) ½ buff, ¼ light, ¼ ring

Question 9:

e) Incomplete dominance:

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