Marble C, with mass 5.0 g, moves at a speed of 20.0 cm/s. It collides with a sec

Question

Marble C, with mass 5.0 g, moves at a speed of 20.0 cm/s. It collides with a second marble, D, with mass 10.0 g, moving at 10.0 cm/s in the same direction. After the collision, marble C continues with a speed of 8.0 cm/s in the same direction. Sketch the situation and identify the system. Identify the "before" and "after" situations and set up a coordinate system. Calculate the marbles!' momentum before the collision. Calculate the momentum of marble C after the collision. Calculate the momentum of marble D after the collision. What is the speed of marble D after the collision?

Explanation / Answer

change to m/s 20cm/s => .2m/s Marble C momentum = mass * velocity momentum = (.005kg)(.2m/s) momentum = .001 kgm/s Marble D momentum = (.01kg)(.1m/s) momentum = .001 kgm/s c) momentum = mass * velocity momentum = (.005kg)(.08m/s) momentum = 4 x 10^-4 kgm/s d) find the velocity of Marble D after the collision (.005kg)(.2m/s) + (.01kg)(.1m/s) = (.005)(.08m/s) + (.01kg)(v) .002 = 4x10^-4 + .01v .0016 = .01v v= .16m/s momentum = (.01kg)(.16m/s) momentum = .0016kgm/s e) v = .16m/s

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