Mcch. 1 A steel ball of mass m is fastened to a light cord of length L and relea
ID: 1916499 • Letter: M
Question
Mcch. 1 A steel ball of mass m is fastened to a light cord of length L and released when the cord is horizontal. At the bottom of its path, the ball strikes a hard plastic block of mass M = 4m, initially at rest on a frictionless surface. The collision is clastic. Find the speed of the ball when its height above its lowest position is 1 /2 L. Write your answer in terms of g and L. Find the net centripetal force exerted on the ball when its height above its lowest position is 1 / 2 L Write your answer in terms of m and g.Explanation / Answer
law of conservation of energy i.e potential +kinetic energy = constant at highest point P.E = mgl at h = l/2, PE = mgl/2 hence K.E = mgl-mgl/2 = mgl/2 a)so V at hieght h = (gl/2)^0.5 b)centripetal force = mv^2/r r = l, v= (gl/2)^0.5 hence centripetal force = mg/2