Liquid butaneis flowing through a pipe of variable diameter. Assume that the flo

Question

Liquid butaneis flowing through a pipe of variable diameter. Assume that the flow is inviscid and steady. At point 1in the pipe, the velocity and pressure are measured to be 32 ft/s and 20 psi. At point 2, the velocity and pressure are 14 ft/s and 23 psi. Determine at which of these two points the elevation is higher. Calculate the height difference. (Assume the sp ecific gravity of butane is 0.6 and that the butane is at a temperature of 15 C.)

Note: please show a step-by-step solution with the correct answer and I'll award you the points
Liquid butaneis flowing through a pipe of variable diameter. Assume that the flow is inviscid and steady. At point 1in the pipe, the velocity and pressure are measured to be 32 ft/s and 20 psi. At point 2, the velocity and pressure are 14 ft/s and 23 psi. Determine at which of these two points the elevation is higher. Calculate the height difference. (Assume the sp ecific gravity of butane is 0.6 and that the butane is at a temperature of 15 C.)

Note: please show a step-by-step solution with the correct answer and I'll award you the points

Explanation / Answer

P/rho + v^2/2 + g*z = Constant

20psi = 2880 lb/ft^2

23 psi = 3312 lb/ft^2

For point 1 :

P/rho + v^2/2 = 2880/rho + 32^2/2 = 20/rho + 512

For point 2:

P/rho + v^2/2 = 3312/rho + 14^2/2 = 23/rho + 98

Now :

g*z1 +   20/rho + 512 = g*z2 + 23/rho + 98

(2880-3312)/rho + 414 = g*(z2-z1)

rho = 0.6* rho (water ) = 0.6*62.4 lb/ft^3

g*(z2-z1) = -432/(0.6*62.4 ) + 414 = -11.5385 + 414 = 402.46 ....it is positive

so Z2 > z1

so Point 2 is at greater elevation

now:

(z2-z1) = 402.46/g = 12.51 ft

g = 32.17 ft/s^2

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