In the figure below, assume that the flux density vector B is uniform and parall
ID: 1927278 • Letter: I
Question
In the figure below, assume that the flux density vector B is uniform and parallel in the region between the N and S poles. B = 0.8 T, L = 0.08 m, W= 0.1 m, and I = 2 A. Take a few minutes to identify the sections of the coil that are subjected to a force due to the magnetic field. Determine the force, F(alpha) on each arm of the coil and the total torque T(alpha) acting on the coil about its axis when: alpha = 00 alpha = 600 alpha = 900 Select the correct answers among the following: F(900) = 0.128 N; T(900) = 0 Nm; F(600) = 0.064 N; T(600) = 0.0064 Nm; F(900) = 0 N; T(900) = 0.16 Nm; F(00) = 0.16 N; T(00) = 0.016 Nm; F(00) = 0.128 N; T(00) = 0.0128 Nm; F(900) = -0.128 N; T(900) = 0.0128 Nm; F(00) = -0.128 N; T(00) = 0.0128 Nm; F(600) = 0.128 N; T(600) = 0.0064 Nm; F(600) = 0.08 N; T(600) = 0.008 Nm;Explanation / Answer
f= l*IXB= bil sin(theta) theta b/w base of coil to normal torque = f*wsin(theta') angle b/w force and distance a) f(0)= 1.6*.08*1 = .128 N t= .128*.1*1 = .0128 Nm b) f(60) = .128 * 1/2 = .064 N t = .064 * .1*1/2 = .0032 Nm c) f(90) = 0