Show all steps and working. Answer in this form (this is how to find the binary
ID: 1944828 • Letter: S
Question
Show all steps and working.
Answer in this form (this is how to find the binary form of 3/10):
Explanation / Answer
Thats precisely how you do it, every time check whether the number is > 1 then multiply it by 2 and so on 3/7 = 0.abcdef... then multiplying by 2 we have 6/7 = a.bcdef.... Hence a = 0 Hence 6/7 = 0.bcdef... then multiplying by 2 we have 12/7 = b.cdefg.... > 1 Hence b = 1 Hence 5/7 = 0.cdefgh.. (subtracting 1 from both sides) then multiplying by 2 we have 10/7 = c.defg.... > 1 Hence c = 1 Hence 3/7 = 0.defgh.. (subtracting 1 from both sides) Hence now it is recurring so 3/7 = 0.011defgh... = 0.defghi... Hence 3/7 = .011 011 011 ....