In the figure below, a small block of mass m = 0.04 kg can slide along the frict

Question

In the figure below, a small block of mass m = 0.04 kg can slide along the frictionless loop-the-loop, with loop radius 13cm. The block is released from rest at point P, at height h = 17R above the bottom of the loop. (For all parts, answer using g for the acceleration due to gravity, and R and m as appropriate.)

In the figure below, a small block of mass m = 0.04 kg can slide along the frictionless loop-the-loop, with loop radius 13cm. The block is released from rest at point P, at height h = 17R above the bottom of the loop. (For all parts, answer using g for the acceleration due to gravity, and R and m as appropriate.) (a) How much work does the gravitational force do on the block as the block travels from point P to point Q? J (b) How much work does the gravitational force do on the block as the block travels from point P to the top of the loop? J (c) If the gravitational potential energy of the block-Earth system is taken to be zero at the bottom of the loop, what is the potential energy when the block is at point P? J

Explanation / Answer

Mass of Block=0.04 kg

Radius of loop = R = 0.13 m

h = 17R

g=9.8 m/s^2

A. Work done by Gravitational Potential Energy as block moves from P to Q = mg(h-R) =16mgR

= 0.815 Joules

B. Work done by Gravitational Potential Energy as block moves from P to top of loop= mg(h-2R)

=15mgR

= 0.7644 Joules

C. Potential Energy at Point P = mgh = 17mgR =0.8663 Joules

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