Consider this reaction step in glycolysis (it is convenient to abbreviate the lo
ID: 195997 • Letter: C
Question
Consider this reaction step in glycolysis (it is convenient to abbreviate the long chemical name).
fructose-6-phosphate (F6P) + phosphate (Pi) --------> fructose-1, 6-bisphosphate (F1, 6BP)
to abbreviate the long chemical names). Utant + fructose-1,6-bisphosphate (F1,6BP) I. Consider this reaction step in glycolysis (it is convenient to abbreviate fructose-6-phosphate (F6P) + phosphate (Pi) fructose-16 Under standard conditions, an initial 1 M solution (cach) of pyruvat concentrations of species at equilibrium: (F6P]=[Pi] = 0.957 M, (F1,6BPI = A. What is the equilibrium constant, Kogº", of this reaction under sts of pyruvate and Pi react to produce the following 55 M. F1,6BP) = 00.043 M. B. What is the free energy change, AG°', of this reaction under standard conditions C. Is this reaction spontaneous under standard conditions? How can you tell?Explanation / Answer
Keq= [fructose 1,6 bisphosphate]/[fructose 6 phosphate][Pi]
= 0.043/0.957*0.957
=0.043/0.915
=0.0470
Delta G = Delta G0 +RTlnKeq
At equilibrium Delta G = 0
So Delta G0 = -RTlnKeq
= -8.314 * 298 * 0.0470
= -116.44 KJ
Yes the reaction is spontaneous as the value of delta G is negative.