<p>Suppose you have to move a heavy crate of weight 875 <img src=\"http://sessio

Question

<p>Suppose you have to move a heavy crate of weight 875 <img src="http://session.masteringphysics.com/render?tex=%7B%5Crm+N%7D" alt="{ m N}" align="middle" /> by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 <img src="http://session.masteringphysics.com/render?tex=%7B%5Crm+N%7D" alt="{ m N}" align="middle" />, but friction prevents the crate from sliding.</p>
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<div class="partText">What is the magnitude <img title="F_p" src="http://session.masteringphysics.com/render?var=F_p" alt="F_p" align="middle" /> of the minimum force you need to exert on the crate to make it start sliding along the floor? Let the coefficient of static friction <img title="mu_s" src="http://session.masteringphysics.com/render?var=mu_s" alt="mu_s" align="middle" /> between the crate and the floor be 0.56 and that of kinetic friction, <img title="mu_k" src="http://session.masteringphysics.com/render?var=mu_k" alt="mu_k" align="middle" />, be 0.47.</div>
<div class="partInstructions">Express your answer numerically in newtons to three significant figures.</div>
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Explanation / Answer

Given data Weight of the crate is, mg = 875 N Magnitude of applied force is, F = 300 N Coefficient of static friction is, s = 0.56 Coefficient of kinetic friction is, k = 0.47 Let the minimum force required to move the crate be Fp Coefficient of kinetic friction is, k = 0.47 Let the minimum force required to move the crate be Fp Solution: The static frictional force is,               fs =  smg                   = (0.56 ) (875 N)                   = 490 N For the crate to slide, we need to apply atlest Fp= 490 N ----------------------------------------------------------------------------- The kinetic frictional force is,               fk =  kmg                   = (0.47 ) (875 N)                   = 411.25 N After the crate slides, the force required to keep the crate to move with constant speed is 411.25 N The kinetic frictional force is,               fk =  kmg                   = (0.47 ) (875 N)                   = 411.25 N After the crate slides, the force required to keep the crate to move with constant speed is 411.25 N

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