5.5 ml of a KMNO4 stock solution is required to titrate theH 2 O 2 remaining aft

Question

5.5 ml of a KMNO4 stock solution is required to titrate theH2O2 remaining after an incubation withcatalase at 25 degrees C. How much KMNO4 would be needed to titratethe solution after performing the incubation at 10 degrees C?

I honestly don't even know where to begin. Everything abouttitration confuses me. I'm not looking for anyone to give me thestraight answer to this question in any way. I'm more or lesslooking for someone to explain to me where to begin with aproblem like this to get an answer. I appreciate any help!

Explanation / Answer

Since the problem give you the required amt to titratethe H2O2, all you need to do is set up a ratio equasion. V1/T1 = V2/T2 V1= 5.5 mL V2 = X T1 = 25'C T2 = 10'C Then do the math answer shoule be 2.2 mL

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