IF YOU CAN PLEASE DO TOP AND BOTTOM QUESTION. MAINLY TOP ONE THANK YOU. In a pop
ID: 197116 • Letter: I
Question
IF YOU CAN PLEASE DO TOP AND BOTTOM QUESTION. MAINLY TOP ONE THANK YOU.
In a population of 1500 fruit flies, the genotypic frequency for individuals that are homozygous recessive for vestigial wings (vg vg) is 0.27, the frequency of heterozygous (vg+vg) individuals is 0.53 and the frequency of homozygous dominant individuals is 0.20 Calculate the genotypic numbers of this population Having a widow's peak is a recessive trait. Out of 1000 individuals 250 have widow's peaks and 450 are heterozygous for the trait. Calculate the genotypic frequencies for the population. Use W and w. Calculate the allele frequencies of this populationExplanation / Answer
As per Hardy-Weinberg Equilibrium, let
p = Frequency of Dominant Allele
q = Frequency of Recessive Allele
Also p + q = 1
Now,
p2 = Frequency of Homozygous Dominant Genotype
2pq = Frequency of Heterozygous Dominant Genotype
q2 = Frequency of Homozygous Recessive Genotype
Here,
p2 = 0.27
2pq = 0.53
q2 = 0.20
Genotypic numbers of this population:
Number of Homozygous Dominant Genotype = p2 * Total = 0.27*1500 = 405
Number of Heterozygous Dominant Genotype = 2pq * Total = 0.53*1500 = 795
Number of Homozygous Recessive Genotype = q2 * Total = 0.20*1500 = 300
Widow's Peak = Recessive Trait. Given:
Total Number = 1000
Number of Homozygous Dominant Genotype WW = 1000 - (450+250) = 300
Number of Heterozygous Dominant Genotype Ww = 450
Number of Homozygous Recessive Genotype ww = 250
Genotypic frequency of Homozygous Dominant Genotype WW = Number / Total = 300/1000 = 0.3
Genotypic frequency of Dominant Genotype Ww = Number / Total = 450/1000 = 0.45
Genotypic frequency of Recessive Genotype ww = Number / Total = 250/1000 = 0.25
Allelic frequency of W = (2*Number of WW + 1* Number of Ww) / 2*Total = (2*300+450)/2000 = 1050/2000 = 0.525
Allelic frequency of 2 = (2*Number of ww + 1* Number of Ww) / 2*Total= (2*250+450)/2000 = 950/2000 = 0.475