The theorem states that I = I cm + Mh2, where I cm is the moment of inertia of t
ID: 1975532 • Letter: T
Question
The theorem states that I = I cm + Mh2, where I cm is the moment of inertia of the object relative to an ax axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and information to determine an expression for moment of inertia of a solid cylinder of radius R relative to an axis that lies on the surface of the cylinder and is perpendicular to the circular ends.Explanation / Answer
MOI of cylinder about its surface = Icm + mr^2 = mr^2/2 +mr^2 = 3mr^2/2