A.) How thick should a sheet of mica (n = 1.58) be if it is to be as thin as pos

Question

A.) How thick should a sheet of mica (n = 1.58) be if it is to be as thin as possible and still give rise to destructive interference for reflection, given that the incident light is in the blue (? = 475.0 nm) part of the spectrum? (mm)

B.) A single-slit diffraction pattern is formed when light of ? = 675.0 nm is passed through a narrow slit. The pattern is viewed on a screen placed one meter from the slit. What is the width of the slit (mm) if the width of the central maximum is 2.43 cm?

C.) What is the minimum thickness of coating which should be placed on a lens in order to minimize reflection of 431 nm light? The index of refraction of the coating material is 1.40 and the index of the glass is 1.65

Explanation / Answer

The refractive index of mica is n = 1.58 The wavelength of the light used is = 475.0 nm The condition for the destructive interference due to thin film is 2t = m For the least possible thickness, m = 1 2t = 2*1.58*t = 475 nm

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