Please don\'t copy and paste a similar answer for this question. Someone did tha
ID: 1982850 • Letter: P
Question
Please don't copy and paste a similar answer for this question. Someone did that for me already and I did my best to follow what they did, but I couldn't arrive at the correct answer. Please check the values used in the question.
Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a 1.20 kg wrench from 7.00 m above the ground and measure that it hits the ground 0.811s later. You also do enough surveying to determine that the circumference of the planet is 6.08×10^4 km. What is the mass of the planet in kilograms and express the planet’s mass in terms of the earth’s mass.
Explanation / Answer
Acceleration of the wrench: s = ut +0.5a*t² 3 = 0 + 0.5*a*0.811² 3 = 0.5*0.658*a a = 3/0.3289 a = 9.122m/s² radius of planet: 6.32*10^7/2p = 1.00586*10^7m a = G*M/r² 9.122 = 6.67300 × 10^-11 * M/(1.00586*10^7)^2 9.122*(1.00586*10^7)^2 = (6.67300*10^-11)*M M = 9.122*(1.00586*10^7)^2 / (6.67300*10^-11) M = 9.229*10^14/(6.67300*10^-11) M =1.384*10^25kg Mass of planet = 1.384*10^25kg Mass of earth = 5.9742 × 10^24 1.384*10^25kg / 5.9742 × 10^24 = 2.315 The planet is 2.315 times as massive as the earth. The mass of the wrench plays no role as acceleration due to gravity is independant of the mass of the object falling.