A block of mass 1.00 sits on an inclined plane as shown. (Intro 1 figure) A forc

Question

A block of mass 1.00 sits on an inclined plane as shown. (Intro 1 figure) A force of magnitude 40.0 is pulling the block up the incline. The coefficient of kinetic friction between the plane and the block is 0.500. The inclined plane makes an angle 40.0 with the horizontal.

1-What is the total work done on the block by the force of friction as the block moves a distance 10.0 up the incline?

2-What is the total work done on the block by the applied force as the block moves a distance 10.0 up the incline?

Explanation / Answer

1) work = - 0.5 * mg*cos@ * d= 0.5 *1*9.8*cos40 *10 = - 37.5 J
2) work = F *d = 40*10 = 400 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---