A neutron collides elastically with a helium nucleus (at rest initially) whose m

Question

A neutron collides elastically with a helium nucleus (at rest initially) whose mass is four times that of the neutron. The helium nucleus is observed to move off at an angle =45. The neutron's initial speed is 6.0×105 .
PART A:Determine the angle of the neutron, , after the collision.
Express your answer using two significant figures.
Q1=?degree
PART B
Determine the speeds of the two particles, and , after the collision.
Express your answers using two significant figures. Enter your answers numerically separated by a comma.
Vn*Vhe=?m/s

Explanation / Answer

conserving momentum, m*5.8*10^5(i) + 0 = 4m*v1(cos45(i) + sin45(j)) + m*v2 where , v2 -->final velocity of nucleus also, conserving energy, .5*m*(5.8*10^5)^2 = .5*(4m)*v1^2 + .5*m*v2^2 solving these two equations, we get, v1 = 1.64*10^5(i+j) v2 = 116000(i) + 463862.1(j) so, angle, f1,= tan-inverse(463862.1/116000) = 76 degrees

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