Part A) Give your answer in component form. (Assume that x -axis is horisontal a

Question

Part A) Give your answer in component form. (Assume that x-axis is horisontal and points to the right, and y-axis points upward.) Express your answer in terms of the unit vectors i^ and j^. Express your answer using two significant figures: E?  =________N/C

Part B) Give your answer as a magnitude and angle measured cw from the positive x-axis. Express your answer using two significant figures. E =__________N/C

Part C) Express your answer using two significant figures: ? = ___________ ? CW from the +x-axis

Explanation / Answer

Sol.:- from the formula E = kq/d^2

E = 9x10^9 x Q/(d^2)

a) 5 nC particle

E1= 9x10^9 x Q/(d^2)

E1= 9x10^9 x (5x10^-9)/(0.02^2) = 112500 N/C (direction east theta1=0)

b) -5 nC particle

E2= 9x10^9 x Q/(d^2)

E2= 9x10^9 x (5x10^-9)/(0.04^2) = 28125 N/C (direction north theta2=90)

c) 10 nC particle

E3= 9x10^9 x Q/(d^2) ;;;;;; d = redical (2^2+ 4^2) = 4.472 cm (Pythagoras)

E3= 9x10^9 x (10x10^-9)/(0.044472^2) = 45000 N/C (direction: theta = -63.43)
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PART A:

Horizontal component : E x = 112500 + 45000.cos 63.43 = 132628.08 N/C
Vertical component : E y = 28125 - 45000 = -12122.48 N/C

====> E = 132628.08 i - 12122.48 j

PART B
Magnitude: E= redical (132628.08^2 +12122.48^2) = 133180.93 N/C
Angle: theta = tan-1 ( -12122.48/132628) = -5.22 degrees = 354.78 degree from + x (CW)

PART C
354.78 degree from + x axis (CW)

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