The solute concentration in blood is equivalent to 0.9% NaCl. In the lab section
ID: 200284 • Letter: T
Question
The solute concentration in blood is equivalent to 0.9% NaCl. In the lab section of Mr. Phil!otson's class, students viewed a sample of blood with a microscope. Next, several drops of blood were added to three different solutions: 0.09% NaCl, 0.9% NaCL and 9% NaCl. (Solutions can be made by adding 9.0 g of NaCl to 100 ml of water to produce 9% NaCl, then mixing 10ml of this solution with 90 ml of water to produce 0.9% NaCl, and mixing 10ml of this solution with 90ml of water to produce 0.09% NaCl). 1. In the figure below, the panel on the left shows how the RBCs appeared in the blood when viewed at 400x magnification. Label the three other panels by indicating which shows RBCs added to 0.09% NaCl, to 0.9% NaCl, and to 9% NaCl. Below the panels, indicate whether each solution is isotonic, hypertonic, or hypotonic in relation to RBCs RBCs in: blood #1= 96 NaCl #2 = % NaCl #3 % NaCl Tonicity:Explanation / Answer
The image looks very representative. The normal behavior of any cell kept in isotonic, hypotonic and hyoertohyp solution is no effect, swollen and shrinkage respectively.
So image 1 represents cells placed in hypertonic solution i.e. 9 percent NaCl, as the cells have shrinked due to high conc. outside because it will lead to flow of water from inside to outside of the cell to maintain tonicity.
The image 2 is isotonic, if we see the figure don't compare it withe cell in blood otherwise you won't be able to correlate. The solution is 0.9 percent here and there is no effect on the cell shape.
The figure 3 shows cells which are swollen that means hypotonic solution I.e. 0.09 percent NaCl. In it water will move inside the cell.