In procedure 2: suppose a beam of monochromatic (single frequency) light, wavele
ID: 2004007 • Letter: I
Question
In procedure 2: suppose a beam of monochromatic (single frequency) light, wavelenth 478 nm falls on a double slit whose slits are 0.0307 mm apart. The screen is 70.3 cm from the slits.a) Calculate the distance from the central maximum to the first maximum.
cm
b) Calculate the distance from the central maximum to the tenth minimum.
cm
3. –/2 points Notes
Suppose procedure 2 is done with a diffraction grating with 487,000 lines per centimeter.
a) Find d, the distance between the lines.
cm
b) Light hits this diffraction grating, and goes onto a screen distance 84.1 cm away, creating a diffraction pattern where the maxima are 21.9 mm apart. Find the wavelength of the light being used. NOTE: the light may not be visible!
nm
Explanation / Answer
In procedure 2: suppose a beam of monochromatic (single frequency) light, wavelenth 478 nm falls on a double slit whose slits are 0.0307 mm apart. The screen is 70.3 cm from the slits.a) Calculate the distance from the central maximum to the first maximum.
cm
b) Calculate the distance from the central maximum to the tenth minimum.
cm Given that wavelength of light = 478 x 10^-9 m slid width is d = 0.0307 x 10^-3m distance between screen and slits is L = 0.703m ------------------------------------------------------------- The condition for the brightness is d sin = m Here m=1 =sin-1[/d] = sin-1[( 478 x 10^-9 m)/(0.0307 x 10^-3m)] = 0.892o So the distance between the centeral maximum to the first maximum is S = L tan 0.892o = (0.703 m) tan( 0.892o) = 0.0109454 m b) The condition for the minimum is d sin = (m + 1/2) Here m =9 d sin = 9.5 = sin-1[(9.5 )/d] = sin-1[(9.5( 478 x 10^-9 m))/(0.0307 x 10^-3m)] = 8.5061 o So the distance from the central maximum to the tenth minimum is S = L tan 8.5061 o = (0.703 m)tan8.5061o = 0.10514 m Note: Please submit question per post as per rules. Note: Please submit question per post as per rules.