Chapter 21, Problem 51 Consult Interactive Solution 21.51 to see how this proble

Question

Chapter 21, Problem 51

Consult Interactive Solution 21.51 to see how this problem can be solved. A coil rotating perpendicularly to a uniform magnetic field contains 390 turns and has an area per turn of 2.5 x 10-3 m2. The magnetic field is 0.093 T, and the current in the coil is 0.12 A. A brake shoe is pressed perpendicularly against the shaft to keep the coil from turning. The coefficient of static friction between the shaft and the brake shoe is 0.56. The radius of the shaft is 0.011 m. What is the magnitude of the minimum normal force that the brake shoe exerts on the shaft?

Explanation / Answer

the torque produced by the brake equal to the maximum torque produced by the coil gives = NIAB sin s FNr = NIAB sin FN =  NIAB sin/sr         = 1.76N

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