17. a. Two identical metal balls carry charges of +3.00uC(+3.00x10^-6 C) and -6.

Question

17. a. Two identical metal balls carry charges of +3.00uC(+3.00x10^-6 C) and -6.00uC. Their centers are 1.00 m apart. Compute the size of the electrical force between them. (k= 9.00 x10^6 Nm^2/C^2)

b. Was the force in part a attractive or repulsive?

c. The balls are allowed to touch each other, so that the electrons are free to move around between the balls, and then they are again placed 1.00 m apart. What is the new charge on each ball?

d. Compute the new electrical force between them.

e. Was the force in part d attractive or repulsive?

Explanation / Answer

a) given that q1=3 x 10-6C q2=-6 x 10-6 C distance between them is r=1m using Coulombs law the electrostatic force F=kq1q2/r2                                       =(9 x 109)(3 x 10-6)(6 x 10-6)/12                                        =0.162N b)sinceone charge is positive and the other is negative the force actinfg between them is attractive c)if the balls are allowed to touch then the net charge is Q=-3 x 10-6C if the two are seperated then each of them contains -1.5 x 10-6C of charge d)the net force between them is F=(9 x 109)(1.5 x 10-6)(1.5 x 10-6)/12 =0.02025N e) since both the charges are negatively charged this force is repulsive =0.02025N e) since both the charges are negatively charged this force is repulsive

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