Question
Pleas show work so as I can follow how to arrive at the solution.
A piece of copper tubing used in plumbing has a lenghth of 60.0 cm and an inner diameter of 1.50 cm. at 20C. When hot water at 85c flows thru the tube, determine
a. the tub's new length
b. the change in its cross-sectional area.
A rod in a steam jacket is measured to have a length of 0.600m. at a temperature of 22.0C Steam is passed through the jacket for several minutes until the rod is at a temperature of 98C. The increase in length of the rod is measured by a micrometer screw to be 1.19mm. Identify the type of metal used.
Explanation / Answer
1 The length of the pipe is L0 = 60 cm The dimeter of the pipe is d = 1.5 cm Initial temperature Ti = 20 oC Final temperature Tf = 85 oC The cofficient of linear expansion of Copper is = 13*10-6 /oC a) L = L0(1 + T) L = (60 cm)(1+(13*10-6 /oC)(65oC)) L = 60.507 cm b) A = A0(2T) A = (0.75 cm)2(2(13*10-6 /oC)(65oC)) A = 0.002985 cm2 2 The initial length L0 = 0.6 m The change in length L = 1.19 mm The initial temperature Ti = 22oC The final temperature is Tf = 98oC The change in length is L = L0T 1.19*10-3 m = (0.6 m)()(76oC) = 2.61*10-5 /oC By the value of the coefficient of thermal expansion the material may be Ytterbium ( = 2.63*10-5 /oC) 2 The initial length L0 = 0.6 m The change in length L = 1.19 mm The initial temperature Ti = 22oC The final temperature is Tf = 98oC The change in length is L = L0T 1.19*10-3 m = (0.6 m)()(76oC) = 2.61*10-5 /oC By the value of the coefficient of thermal expansion the material may be Ytterbium ( = 2.63*10-5 /oC)