A single loop of copper wire moves at an unknown constant speed v into a region

Question

A single loop of copper wire moves at an unknown constant speed v into a region of uniform magnetic field B = 2.50 T. The magnetic field points into the page inside the region with crosses. The magnetic field is everywhere else zero. The resistivity of copper is ? = 1.70x10-8 O-m and the cross sectional diameter of the copper wire is 0.800 mm. The magnitude of the induced voltage in the copper wire loop is e = 4.00 V.

a) Calculate the resistance of the copper wire loop (You may use ohms in place of O).
b) Calculate the induced current in the copper wire loo

Explanation / Answer

Given that N =1 magnetic field B = 2.50 T resistivity of copper =  1.70x10^-8 .m radius r = 0.80 x 10^-3 m ------------------------------------------------------- The resistance of the copper wire is               R = L/(r^2) Length of the copper wire is L = 2r               R = ( 2r)/(r^2)                   = 2/(r)                  = 2(1.70x10^-8 .m)/( 0.80 x 10^-3 m)                  = 4.25 x10^-5 b) The induced current in the circuit is                  I = e/R Here induced emf is e = 4.00 V                 I = (4.00 A)/( 4.25 x10^-5 )                    =9.4 x 10^+4 A b) The induced current in the circuit is                  I = e/R Here induced emf is e = 4.00 V                 I = (4.00 A)/( 4.25 x10^-5 )                    =9.4 x 10^+4 A

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