a) Five identical resistors, each of resistance R, are connected in series to a
ID: 2009476 • Letter: A
Question
a) Five identical resistors, each of resistance R, are connected in series to a battery, and a current of 3.43 A flows in the circuit. Now, another resistor of resistance R is added to the circuit, in series with the rest of the resistors. Find the new current in the circuit.
_____ A
b) Five identical resistors, each of resistance R, are connected in parallel to a battery, and a current of 3.43 A flows in the circuit. Now, another resistor of resistance R is added to the circuit, in parallel with the rest of the resistors. Fnd the new current in the circuit.
_____ A
c) Five identical resistors, each of resistance R, are connected in series to a battery, and a current of 3.43 A flows in the circuit. Now, another resistor of resistance R is added to the circuit, in parallel with the battery. Find the new total current in the circuit.
______A
What I did (It said I was wrong):
Let E be the emf of the battery.
Resistance of each resistor = R
Current I = 2.86 A
(a)
Total resistance = 5R
So Emf E = I 5R = 3.43*5*R = 17.15 R
New current in the circuit I' = E/6R = 14.3R/6R = 2.86 A
(b)
Total resistance = R/5
So Emf E = I R/5 = 3.43*R/5 = 0.686 R
New current in the circuit I' = E/(R/6) = 6E/R = 4.12 A
(c)
Total resistance = 5R
So Emf E = I 5R = 3.43*5*R = 17.15 R
New current in the circuit I' = E/[(5R*R)/(5R + R)]
= 17.15 R/(5R/6)
= 20.58 A