1 ) A 0.50-kg mass is suspended from a string, forming a pendulum. The period of

Question

1 ) A 0.50-kg mass is suspended from a string, forming a pendulum. The period of this pendulum is 4.1 s when the amplitude is 1.6 cm. The mass of the pendulum is now reduced to 0.21 kg. What is the period of oscillation now, when the amplitude is 1.4 cm? unit in s

2 ) A bob of mass m is suspended from a string of length L, forming a pendulum. The period of this pendulum is 4.0 s. If the pendulum bob is replaced with one of mass
1/3 m and the length of the pendulum is increased to 2L, what is the period of oscillation? unit in s

Explanation / Answer

given that b)   intila string length is L final string slength   is 2L intial masss m final mass is 1/3 m    intial time period T = 4.0s from the time period of the pendulum time period is depend on length only not in mass    TL    for   intial length TL for final length T1 2L then T/T1 L/2L         T1 = 2L/ L * T               = 5.656 s a) intial mass m1 = 0.50 kg final mass m2 = 0.21kg intial time period T1 = 4.1s tim eperiod of pendulum does not depend on amplitude and mass   it depend only on the length of string   and accleration due to gravity so time period does not alter its time period i s T2 = 4.1s

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