<p>A <span style=\"white-space: nowrap;\">0.700</span>&#160;<img src=\"http://se

Question

<p>A <span>0.700</span>&#160;<img src="http://session.masteringphysics.com/render?units=%7B%5Crm+kg%7D" alt="{ m kg}" align="middle" /> wood block is firmly attached to a very light horizontal spring (<img title="k" src="http://session.masteringphysics.com/render?var=k" alt="k" align="middle" />&#160;=&#160;<span>160</span>&#160;<img src="http://session.masteringphysics.com/render?units=%7B%5Crm+N%2Fm%7D" alt="{ m N/m}" align="middle" />) as shown in the figure . This block-spring system, when compressed <span>4.7</span>&#160;<img src="http://session.masteringphysics.com/render?units=%7B%5Crm+cm%7D" alt="{ m cm}" align="middle" /> and released, stretches out <span>2.5</span>&#160;<img src="http://session.masteringphysics.com/render?units=%7B%5Crm+cm%7D" alt="{ m cm}" align="middle" /> beyond the equilibrium position before stopping and turning back.</p>
<div class="partText">What is the coefficient of kinetic friction between the block and the table?</div>

Explanation / Answer

The mass of the block of wood is m = 0.70kg The spring constant of the spring is k = 160 N/m The block spring system is compressed by x = 4.7 cm = 4.7 *10-2 m Let the coefficient of kinetic friction between the block andthe table be k. The force on the spring is F = -kk * x ---------(1) or F = -160 * 4.7 * 10-2 = -k 7.52 N The negative value of force indicates that the force iscompressed. We know that F = m * g ---------(2) From equations (1) and (2),we get m * g = 7.52 k or k= (0.70 * 9.8/7.52) = 0.9 The coefficient of kinetic friction between the block and thetable is 0.9.

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