In the diagram above: current-carrying wires are wrapped around the square solen
ID: 2011341 • Letter: I
Question
In the diagram above: current-carrying wires are wrapped around the square solenoid of side a, length L, and n turns per meter. Assume the current runs clockwise (looking head-on).
a) At the geometric center of the cavity inside the solenoid: the magnetic field
1) points away from you, into the page
2) points to the left
3) points toward you, out of the page
4) points downward
5) is approximately zero
6) points upward
7) points to the right
b) Suppose we put current I through the coil, and the magnetic field at the center of the cavity is B. If we now double three quantites: side a, number of turns per meter .n and length L, the new mangetic field at the center of the cavity will be
1) 3B
2) B/3
3) 4B
4) B/4
5) B/2
6) 2B
7) B
NOTE: In MKS units: T is Tesla, A is amperes, V is volts.
c) Using an equation for magnetic field: the units of o can be expressed as
1) T-A/m
2) T-m/s
3) T-s/m
4) A/T-m
5) A-m/T
6) T-s/A
7) T-m/A
8) T-A/V
9) A/T-s
10) T-s/V
d) The instructions tell you to zero the magnetic field sensor before turning it up. If you do not do this, then for each trial:
1) there will be random fluctuation in the power supply votage, and in the currents
2) the current might spike, and burn out the coil
3) the magnetic field sensor readings will be off by a fixed amount
4) voltages from the power supply, and the currents, will be off by a fixed amount
5) there will be random errors in the magnetic field sensor readings
Explanation / Answer
A) points downward
B) 2B
C) T- m/A
D) magnetic field sensor off by fixed amount