For this assignment, the number of submissions for each answer box is counted in

Question

For this assignment, the number of submissions for each answer box is counted independently. The number of submissions remaining changes only if you submit a new or changed answer.
1. –/2 points Notes Question: SerCP8 2.P.056.
A speedboat moving at 34.0 m/s approaches a no-wake buoy marker 100 m ahead. The pilot slows the boat with a constant acceleration of -3.65 m/s2 by reducing the throttle.
(a) How long does it take the boat to reach the buoy?
s

(b) What is the velocity of the boat when it reaches the buoy?
m/s

Explanation / Answer

Given that a speed of the boat is u = 34.0m/s distance s = 100m   The pilot slows the boat with a constant acceleration is a = - 3.65 m/s^2 b ) the velocity of the boat when it reaches the buoy                 v^2 - u^2 = 2as                v^2 = ( 34.0m/s)^2 - 2 * 3.65 m/s^2 * 100m                v = 20.6 m/s a ) time  it take the boat to reach the buoy is        v = u + at      20.6 m/s = 34.0 m/s - 3.65m/s^2 * t       t = 3.67 s

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---