1) A massless rod of length 1.00 m has a 6.00-kg mass attached to one end and a

Question

1) A massless rod of length 1.00 m has a 6.00-kg mass attached to one end and a 12.0-kg mass attached to the other. The system rotates about a fixed axis perpendicular to the rod that passes through the rod 30.0 cm from the end with the 6.00-kg mass attached. What is the moment of inertia of this system about this axis? Give your answer in SI units

answer is 6.42,sho the steps please
2) A solid sphere of mass 1.5 kg and radius 10 cm rolls without slipping down a 30° incline that is 6.0 m long. Assume it started from rest. The moment of inertia of a sphere is given by I= (2/5)MR2. Determine the angular speed of the sphere in rad/s at the bottom of the incline.

answer is 65, can someone show the steps?

Explanation / Answer

Given that the masses are m1 = 6.00 kg and m2 = 12.0 kg Separation between two masses is d = 1.00 m ------------------------------------------------------------- Separation between the mass m1 and axis of rotation is                 x1 = 30.0cm = 0.30 m Separation between the mass m2 and axis of rotation is                 x2 = d - 30.0cm                     = 0.70 m Moment of inertia of the system about the axis of rotation is             I = m1*x12 + m2*x22               = (6.00 kg)*(0.30m)2 + (12.0 kg)*(0.70m)2               = 6.42 kg.m2                              = (6.00 kg)*(0.30m)2 + (12.0 kg)*(0.70m)2               = 6.42 kg.m2               

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