A hollow box encloses a net charge of -4.8 x 10^-9 C. The electric flux through
ID: 2018788 • Letter: A
Question
A hollow box encloses a net charge of -4.8 x 10^-9 C. The electric flux through the top surface of the box is 250 Vm. The electric flux through the front, back, left, and right sides is zero. What is the electric flux through the bottom surface?A. 292 Vm
B. 792 Vm
C. -542 Vm
D. -292 Vm
E. -792 Vm
Im studying for an exam in a couple hours, so I'll give anyone the "Extremely Helpful" if you can provide a detailed explaination for why this is so. (The integral of Electric field and area is part of it?) thanks
Explanation / Answer
Using Gauss's law, we have
electric flux (top) + electric flux(bottom) = Q /
electric flux(bottom) = Q / - electric flux (top)
= -4.8*10-9 / 8.85*10-12 - 250
= -792 Vm
answer is E