Chapter 7 Lesson 7 See example 8 Pg. 208 Ballistic Pendulum An object (the proje

Question

Chapter 7 Lesson 7
See example 8
Pg. 208
Ballistic Pendulum

An object (the projectile) strikes and becomes embedded in a block of wood suspended from the ceiling by 2 strings of negligible mass. You will be asked to read the measurement tables and make calculations concerning total mechanical energy and momentum (energy and momentum are conserved since friction and air resistance are absent). These measurements will result in the determination of the initial velocity of the projectile (actually the initial velocity and the velocity on impact are identical).
Find the time, t, that the bullet embedded in the block of wood reaches its maximum height.
t = 0.794 seconds
If h = ?y = yf – yi, where h is the change in height of the block of wood at equilibrium to its maximum height, from the position measurement table, determine h.
h = + 0.194 m
Calculate the velocity of the bullet.
v = +101.3987 m/s
v = (m + M/m) v2gh
v =[ (0.001 kg + .051 kg)/0.001] v2(9.80 m/s2)(0.194 m) =
v = 0.052 kg/ 0.001 = 52 v3.8024 = 101.3987 m/s

mass of bullet= m = .001 kg
Mass of block = M = .051 kg
Start: x0 = 1.452 m
Y0 = - 0.984 m
End: x1 = 2.367 m
Y1 = - 0.790 m

h = ?y = yf – yi,
h = - 0.790 m - - 0.984 m = 0.194 m

Explanation / Answer

mass of bullet m = 0.01kg mass of the block, M = 0.051kg Applying the conservation of momentum, the velocity, V = [m/(m+M)]v the requared to maximum height , t =  [m/(m+M)]v/g = 0.794 s the bullet embedded in the block of wood reaches its maximum height is 0.794 ms. your work is well. mass of bullet m = 0.01kg mass of the block, M = 0.051kg Applying the conservation of momentum, the velocity, V = [m/(m+M)]v the requared to maximum height , t =  [m/(m+M)]v/g = 0.794 s the bullet embedded in the block of wood reaches its maximum height is 0.794 ms. your work is well.

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