Use the worked example above to help you solve this problem. A skier starts from

Question

Use the worked example above to help you solve this problem. A skier starts from rest at the top of a frictionless incline of height 20.0 m, as shown in the figure. As the bottom of the incline, the skier encounters a horizontal surface where the coefficient of kinetic friction between skis and snow is 0.214.

(a) Find the skier's speed at the bottom. = 19.8

(b) How far does the skier travel on the horizontal surface before coming to rest? = 93.6

I NEED HELP WITH NEXT QUESTION..

Use the values from PRACTICE IT to help you work this exercise. Find the horizontal distance the skier travels before coming to rest if the incline also has a coefficient of kinetic friction equal to 0.214. (The incline makes an angle ? = 20.0° with the horizontal.)

Explanation / Answer

from figure , sin = h/L length of the incline L = h/sin                                  = (20 m) /sin20                                  = 58.476 m the coefficient of kinetic friction between skis and snow k = 0.214 speed v = {2gL(sin - k cos)}               ={(2)(9.8 m/s2)(58.476 m)(sin20 - (0.214) cos20)}                = 12.71 m/s then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2)                     = 38.51 m then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2)                     = 38.51 m then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2)                     = 38.51 m then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (12.71 m/s) 2/ (2)(0.214)(9.8 m/s2)                     = 38.51 m

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---