The figure is a graph of the force exerted by the floor on a woman making a vert

Question

 

The figure is a graph of the force exerted by the floor on a woman making a vertical jump. At what speed does she leave the ground?

HINT: The force of the floor is not the only force acting on the woman. The answer is around 3.xx m/s (cant remember exactly-dont have the book).

Here is what im doing and getting the wrong answer:

I split it up into two triangles and a rectangle:

1/2(.2s)(1800N)=180kgXm/s
1/2(.1s)(2400N)=120kgXm/s
.2(600N)=120kgXm/s

180kgXm/s+120kgXm/s+120kgXm/s=420kgXm/s

420kgXm/s/61.22kg (weight of the girl)=6.86 m/s

The figure is a graph of the force exerted by the floor on a woman making a vertical jump. At what speed does she leave the ground? HINT: The force of the floor is not the only force acting on the woman. The answer is around 3.xx m/s (cant remember exactly-dont have the book). Here is what im doing and getting the wrong answer: I split it up into two triangles and a rectangle: 1/2(.2s)(1800N)=180kgXm/s 1/2(.1s)(2400N)=120kgXm/s .2(600N)=120kgXm/s 180kgXm/s+120kgXm/s+120kgXm/s=420kgXm/s 420kgXm/s/61.22kg (weight of the girl)=6.86 m/s

Explanation / Answer

I been getting 8.8 m/s, looks like that wrong. But if you find the sum of the area using calculus, your ans is 3.9 m/s w/ 2sf.

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