You just calibrated a constant volume gas thermometer. The pressure of the gas i

Question

You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 238 kPa when the thermometer is in contact with boiling water. (The boiling water is under regular atmospheric pressure.) What is the temperature of the thermometer, when it reads a pressure of 502 kPa?


Please show all work an answer in sig-figures

Thank you

Hint!!
Before using that relationship, you must convert the temperature to Kelvin. The pressure can be left in kPa; converting to atm. will yield the same result because the two pressures differ by the same conversion factor and this conversion factor will cancel out.

Boiling Point in Kelvin=373.15. Units are in degC

Explanation / Answer

from gas law ,PV=nRT

at constant volume P/T =constant

hence P1/T1 =P2/T2

implies T2=P2(T1)/(P1) = (502)(373.15)/(238) =787.06 K

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---