1) Two isotopes of carbon, carbon-12 and carbon-13, have masses of 1.993x10^-26

Question

1)

Two isotopes of carbon, carbon-12 and carbon-13, have masses of 1.993x10^-26 kg and 2.159 x 10^-26 kg, respectively. These two isotopes are singly ionized (+e) and each is given a speed of 6.88 x10^5 m/s. The ions then enter the bending region of a mass spectrometer where the magnetic field is 0.8700 T. Determine the spatial separation between the two isotopes after they have traveled through a half-circle.

2)

A copper rod of length 0.91 m is lying on a frictionless table (see the drawing). Each end of the rod is attached to a fixed wire by an unstretched spring that has a spring constant of k = 76 N/m. A magnetic field with a strength of 0.17 T is oriented perpendicular to the surface of the table.

If the current is 13 A, by how much does each spring stretch?

Explanation / Answer

The spatial difference between two isotopes after they have travelled through a half circle is         d = 2( r_2 - r_1 )                = 2 ( m_2 v / eB )( - 2 ( m_1 v / e B )                = (2 v / e B ) ( m_2 - m_1 )        masses of two isotopes are m_2 = 2.159*10^-26 kg , m_1 = 1.993*10^-26 kg        speed of the isotopes is v = 6.88*10^5 m/s             magnetic field is B = 0.8700 T    d = 2 * 6.88*10^5 m/s / 1.6*10^-19 C * 0.8700T (  2.159*10^-26 kg - 1.993*10^-26 kg )            = 0.0164m           = 1.64 cm according to cramster rule only one question to be answerd please post second question another post i will answer you thank u ( please give figure )

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