Two astronauts on opposite ends of a spaceship are comparing lunches. One has an
ID: 2029966 • Letter: T
Question
Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.115 kg apple toward astronaut 2 with a speed of v1 1.14 m/s The 0.150 kg orange is tossed fronm astronaut 2 to astronaut 1 with a speed of 1.25 m/s Unfortunately, the fruits collide, sending the orange off with a speed of 1.02 m/s in the negative y direction. Part A What are the final speed and direction of the apple in this case? Before tif m s Submit Request Answer Part B After 0 ° counterclockwise from the positive x axis Submit Request AnswerExplanation / Answer
Given :
Mass of Apple (m1) = 0.115 kg
Initial velocity (u1) = ( 1.14 i ) m/s
.Mass of Orange (m2) = 0.150 kg
Initial velocity (u2) = ( - 1.25 i ) m/s
Final velocity of Orange (v2) = ( - 1.02 j ) m /s
From conservation of momentum :
m1 u1 + m2 u2 = m1 v1 + m2 v2
.m1 v1 = ( m1 u1 + m2 u2 ) - m2 v2
m1 v1 = ( 0.115 * 1.14 i + 0.150 * -1.25 i ) - ( 0.150 * -1.02 j )
m1 v1 = 0.149 i + 0.1976 j
v1 = (-0.174 i + 0.153 j) /0.115
v1 = -1.513 i + 1.33 j
Hence magnitude is
v1 = sqrt [ (1.513)2 + (1.33)2 ]
v1 = 2.01 m/s
Direction is :
= tan-1 ( 0.153 / -0.174 )
= -41.32 degree or 138.68 degree