Piston 1 in the figure has a diameter of 1.75 cm. 2 in. 1 0 in Piston 2 has a di

Question

Piston 1 in the figure has a diameter of 1.75 cm. 2 in. 1 0 in Piston 2 has a diameter of 7.41 cm. In the absence of friction, determine the force required on piston 1 necessary to support an object with a mass of 836 ka placed on piston 2. (Neglect the height difference between the bottom of thè two pistons, and assume that the pistons ae massless) 495.3 N Submit Answer Incorrect. Tries 1/20 Previous Tries What is the magnitude of the force F, required at the end of the handle? mAnser Tries 0/20

Explanation / Answer

Ans 1)

We know that F1/ A1 = F2/A2 by newtons law of viscosity

F1/(pi*((0.0175/2)*(0.0175/2)) = 836*9.8/(pi*((0.0741/2)*(0.0741/2)))

F1 =456.95 N

Ans 2)

At equillibrium

F1R1 - F*R2 = 0

R1 = 2 Inch = 2*0.051 m

R2 = 10 inch = 10*0.051 m

F1 = 836*9.8 N

F = F1R1/R2

F = 836*9.8*2*0.051/(10*0.051) = 1638.56 N

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---