The res stors in the circuit below have the following values: R1-7.4 ? R2-7.0 ?

Question

The res stors in the circuit below have the following values: R1-7.4 ? R2-7.0 ? and R3 370·The two batteries each have a voita ofs . R2 R1 R3 (a) Find the current in through R3 Is it possible to reduce the circuit by considering series and/or parallel combination of resistors? What is the total current delivered by the batteries? What is the voltage across R3? A (b) How much power do the batteries deliver to R3? What is the basic relationship for power in terms of current and resistance? W Need Help?ReadIt Submit Answer Save Progress

Explanation / Answer

R2 and R3 are in parallel, So

R23 = R2*R3/(R2 + R3)

R23 = 7*3.7/(7 + 3.7) = 2.42 ohm

Now R23 and R1 are in series, So

Req = R23 + R1 = 2.42 + 7.40

Req = 9.82 ohm

Using ohm's law:

V = i*Req

i = (5 + 5)/9.82 = 1.02 Amp

Now remember in resistors parallel combination voltage distribution in each part will be same and in series combination current distribution in each resistor will be same.

Current in R1 = Current in R23 = 1.02 Amp

Voltage in R23 = i23*R23

V23 = 1.02*2.42 = 2.47 V

Now Since R2 and R3 are in parallel, So

V2 = V3 = V23 = 2.47 V

Now Current in R3 will be

i3 = V3/R3 = 2.47/3.70

i3 = 0.67 Amp

B.

Power in R3 will be

P3 = V3*i3

P3 = 2.47*0.67

P3 = 1.65 W

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