A beam of protons is moving in the + x direction with a speed of 16.5 km/s throu

Question

A beam of protons is moving in the +x direction with a speed of 16.5 km/s through a region in which the electric field is perpendicular to the magnetic field. The beam is not deflected in this region. If the magnetic field has a magnitude of 0.827 T and points in the +z direction,

A.) what is the magnitude of the electric field? _________

B.) Would electrons that have the same velocity as the protons be deflected by these fields? If so, in what direction would they be deflected?

FOR PART B PLEASE PICK ONE OF THE YES/NO ANSWERS BELOW

__ Yes, -z
Yes, +x
No
Yes, -x
Yes, +z
Yes, -y
Yes, +y

HINT/CLARIFICATION  

Explanation / Answer

given

v = 16.5 km/s = 16500 m/s
B = 0.827 T

A) for no deflection,

Fe = FB

q*E = q*v*B

E = v*B

= 16500*0.827

= 1.36*10^4 N/C

B) No

because, elctrons and protons have same magnitude of charge.

so, magnitude of force on electrons same as on protons.

so, net force becomes zero.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects